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# offset image challenges
Coding challenges for the offset image tutorial. #docs
## Before we get started
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Complete the following exercise. Your code should look like this:
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```blocks
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offset = 0
basic.forever(() => {
if (offset == -4) {
basic.showString("Push button A", 150)
}
images.createImage(`
. . # . .
. . # . .
. . # . .
. # # # .
. . # . .
`).showImage(offset)
})
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input.onButtonPressed(Button.A, () => {
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offset = offset + 1
})
```
### Challenge 1
Create a condition for if button `B` is pressed. We want the image to move to the left when button `B` is pressed.
```
offset = 0
basic.forever(() => {
if (offset == -4) {
basic.showString("Push button A", 150)
}
images.createImage(`
. . # . .
. . # . .
. . # . .
. # # # .
. . # . .
`).showImage(offset)
})
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input.onButtonPressed(Button.A, () => {
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offset = offset + 1
})
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input.onButtonPressed(Button.B, () => {
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offset = offset - 1 // ** *
}) // ** *
```
* Run the code to see if it works as expected.
### Challenge 2
### @video td/videos/offset-image-2
Now we want to make sure that the button does not go off the screen to the right. Add a new line that checks to see if offset = 5 after button `A` is pressed.
If `offset = 5` then prompt the user to move the image to the left by displaying the text: "Push button B".
```
offset = 0
basic.forever(() => {
if (offset == -4) {
basic.showString("Push button A", 150)
}
if (offset == 5) {
basic.showString("Press Button B", 150) // ** *
}
images.createImage(`
. . # . .
. . # . .
. . # . .
. # # # .
. . # . .
`).showImage(offset)
})
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input.onButtonPressed(Button.A, () => {
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offset = offset + 1
})
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input.onButtonPressed(Button.B, () => {
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offset = offset - 1
})
```
* Run the code to see if it works as expected.
**Challenge 3**
Now make sure the image does not go off the left side and if it does, prompt the user to push button `A` .