* Spelling mistakes
4.3 KiB
Code
Let's build the code that, when the user presses the button A on a @boardname@, will send an impulse over a wire to the receiving @boardname@ and turn on an LED there.
Make sure that the sending and receiving wires run "symmetrically" between the two boards. That is: pin 1 on one @boardname@ is connected to pin 2 on the other, and vice versa. Just like it's shown in the pictures in the make section. This way we can use the same code on both @boardname@s .
Step 1
We start with a block that digitally writes high value (a digital 1
) to P1
which sends the value to @boardname@'s pin 1. This block is found in Pins drawer of the Advanced section of the Toolbox.
pins.digitalWritePin(DigitalPin.P1, 1)
Step 2
To show that we are sending the 1
, we add a block to turn on an LED in the center of the LED display (2, 2) using ||led:plot x y||
:
pins.digitalWritePin(DigitalPin.P1, 1)
led.plot(2, 2)
Step 3
Now that we know how to send the signal, we only want to do it while the button A is pressed.
Pick an ||logic:if then else||
block from the Logic drawer (you'll leave the ||logic:else||
part empty for now). Add a check for when button A is pressed. Get an ||input:on button pressed||
from the Input drawer and move the blocks from the previous step into ||logic:then||
part of the ||logic:if then else||
:
if (input.buttonIsPressed(Button.A)) {
pins.digitalWritePin(DigitalPin.P1, 1)
led.plot(2, 2)
} else { }
Step 4
For the ||logic:else||
section (while button A is not pressed) we want to do the opposite of what we did in the |logic:then||
section. Which is, make the value of pin P1
go to low (digital 0) and unplot the corresponding LED on the sending @boardname@:
if (input.buttonIsPressed(Button.A)) {
pins.digitalWritePin(DigitalPin.P1, 1)
led.plot(2, 2)
} else {
pins.digitalWritePin(DigitalPin.P1, 0)
led.unplot(2, 2)
}
Step 5
Let's wrap it all in a forever loop so this code is running in the background always checking button A and sending the appropriate signal to the receiver. Modify your code to add the blocks below. Download the code onto one of the @boardname@s, press and release button A a few times.
basic.forever(() => {
if (input.buttonIsPressed(Button.A)) {
pins.digitalWritePin(DigitalPin.P1, 1)
led.plot(2, 2)
} else {
pins.digitalWritePin(DigitalPin.P1, 0)
led.unplot(2, 2)
}
})
The sending part is done, so now we'll add the receiving part.
Step 6
The receiver needs to digitally read from the pin where the other @boardname@ sends its value to pin 2 across the wire. Let's start by going to the Pins drawer, adding a ||pins:digital read pin||
and change the pin value to P2
.
Now, we want to examine the value read from P2
and check whether it's high (1
) or low (0
). Go to the Logic drawer and pick an ||logic:if then else||
block, then come back for the comparison operator ||logic:0 = 0||
. Plug in our ||pins:digital read pin||
block as one operand and the value 1
as the other.
We'll turn the LED in the bottom right corner (4, 4) on to show that we received a high value and turn it off in not.
Make sure your code looks like this:
basic.forever(() => {
if (input.buttonIsPressed(Button.A)) {
pins.digitalWritePin(DigitalPin.P1, 1);
led.plot(2, 2);
} else {
pins.digitalWritePin(DigitalPin.P1, 0);
basic.clearScreen();
}
if (pins.digitalReadPin(DigitalPin.P2) == 1) {
led.plot(4, 4);
} else {
led.unplot(4, 4);
}
});
Your telegraph is ready!
Step 7
Ok, let's try it out:
- Connect the first @boardname@ to your computer using your USB cable and download the telegraph code to it.
- Disconnect the first @boardname@.
- Connect the second @boardname@ to your computer using your USB cable and download the telegraph code to it.
- Disconnect the second @boardname@.
- Connect the battery holder to one of the @boardname@s.
- The first person, and then second person, can take turns pressing button A on their own @boardname@s to play the telegraph game!