2.0 KiB
2.0 KiB
offset image challenges
Coding challenges for the offset image tutorial. #docs
Before we get started
Complete the following guided tutorial:
At the end of the tutorial, click keep editing
. Your code should look like this:
offset = 0
basic.forever(() => {
if (offset == -4) {
basic.showString("Push button A", 150)
}
images.createImage(`
. . # . .
. . # . .
. . # . .
. # # # .
. . # . .
`).showImage(offset)
})
input.onButtonPressed(Button.A, () => {
offset = offset + 1
})
Challenge 1
Create a condition for if button B
is pressed. We want the image to move to the left when button B
is pressed.
offset = 0
basic.forever(() => {
if (offset == -4) {
basic.showString("Push button A", 150)
}
images.createImage(`
. . # . .
. . # . .
. . # . .
. # # # .
. . # . .
`).showImage(offset)
})
input.onButtonPressed(Button.A, () => {
offset = offset + 1
})
input.onButtonPressed(Button.B, () => {
offset = offset - 1 // ***
}) // ***
- Run the code to see if it works as expected.
Challenge 2
@video td/videos/offset-image-2
Now we want to make sure that the button does not go off the screen to the right. Add a new line that checks to see if offset = 5 after button A
is pressed.
If offset = 5
then prompt the user to move the image to the left by displaying the text: "Push button B".
offset = 0
basic.forever(() => {
if (offset == -4) {
basic.showString("Push button A", 150)
}
if (offset == 5) {
basic.showString("Press Button B", 150) // ***
}
images.createImage(`
. . # . .
. . # . .
. . # . .
. # # # .
. . # . .
`).showImage(offset)
})
input.onButtonPressed(Button.A, () => {
offset = offset + 1
})
input.onButtonPressed(Button.B, () => {
offset = offset - 1
})
- Run the code to see if it works as expected.
Challenge 3
Now make sure the image does not go off the left side and if it does, prompt the user to push button A
.